Dynamisch draaien van een tabel Oracle

Dit kan op de volgende manier dynamisch worden gedaan. Ten eerste is hier de statische versie van de query, zodat u de uiteindelijke sql kunt zien:

select c_id,
  p_id,
  max(case when r_key= 'KEY1' then r_value  end) KEY1,
  max(case when r_key= 'KEY2' then r_value  end) KEY2,
  max(case when r_key= 'KEY3' then r_value  end) KEY3,
  max(case when r_key= 'KEY4' then r_value  end) KEY4,
  max(case when r_key= 'KEY5' then r_value  end) KEY5
from s_projectroles
group by c_id, p_id

Zie SQL Fiddle met demo

Om dit vervolgens dynamisch te doen, kunt u de volgende procedure maken:

CREATE OR REPLACE procedure dynamic_pivot(p_cursor in out sys_refcursor)
as
    sql_query varchar2(1000) := 'select c_id, P_id ';

    begin
        for x in (select distinct r_key from s_projectroles order by 1)
        loop
            sql_query := sql_query ||
              ' , max(case when r_key = '''||x.r_key||''' then r_value end) as '||x.r_key;

                dbms_output.put_line(sql_query);
        end loop;

        sql_query := sql_query || ' from s_projectroles group by c_id, p_id';

        open p_cursor for sql_query;
    end;
/

Om het vervolgens uit te voeren:

variable x refcursor
exec dynamic_pivot(:x)
print x

Het resultaat is hetzelfde:

|   C_ID |   P_ID |   KEY1 |   KEY2 |   KEY3 |   KEY4 |   KEY5 |
----------------------------------------------------------------
| (null) | (null) | VALUE1 | VALUE2 | VALUE3 | (null) | (null) |
|      2 |      2 | (null) | (null) | (null) | VALUE4 | (null) |
|      2 |      3 | (null) | (null) | (null) | (null) | VALUE5 |