Probeer:
SELECT cu.ID , cu.ADI_NUMARASI , co.ID , co.VALUE
FROM
(
SELECT id,ADI_NUMARASI,TYPEIDS,DOMAINID,
regexp_substr(TYPEIDS,'[^,]+', 1, level) typeidsnew
FROM Customer
GROUP BY id,ADI_NUMARASI,TYPEIDS,DOMAINID,
regexp_substr(TYPEIDS, '[^,]+', 1, level)
connect by regexp_substr(TYPEIDS, '[^,]+', 1, level) is not null
) cu
LEFT JOIN Code co ON cu.typeidsnew = co.ID
AND cu.DomainId = co.domainId
ORDER BY cu.ID,co.ID
Uitvoer:http://sqlfiddle.com/#!4/177e8/1