U mag AddWithValue
. gebruiken methode zoals:
string connString = ConfigurationManager.ConnectionStrings["default"].ConnectionString;
MySqlConnection conn = new MySqlConnection(connString);
conn.Open();
MySqlCommand comm = conn.CreateCommand();
comm.CommandText = "INSERT INTO room(person,address) VALUES(@person, @address)";
comm.Parameters.AddWithValue("@person", "Myname");
comm.Parameters.AddWithValue("@address", "Myaddress");
comm.ExecuteNonQuery();
conn.Close();
OF
Probeer het met ?
in plaats van @
, zoals:
string connString = ConfigurationManager.ConnectionStrings["default"].ConnectionString;
MySqlConnection conn = new MySqlConnection(connString);
conn.Open();
MySqlCommand comm = conn.CreateCommand();
comm.CommandText = "INSERT INTO room(person,address) VALUES(?person, ?address)";
comm.Parameters.Add("?person", "Myname");
comm.Parameters.Add("?address", "Myaddress");
comm.ExecuteNonQuery();
conn.Close();
Ik hoop dat het helpt...