Een slechte database herstructureren met PHP-loops of MySQL

Er is geen PHP nodig. Je kunt het alleen doen met pure MySQL-code.

Tafel maken/tabel invoegen

CREATE TABLE HugeTable
    (`Column1` VARCHAR(11), `Column2` VARCHAR(11), `Column3` VARCHAR(11))
;

INSERT INTO HugeTable
    (`Column1`, `Column2`, `Column3`)
VALUES
    ('Data1;Data2', 'Data3;Data4', 'Data5;Data6')
; 

CREATE TABLE NewTable
   (`Column1` VARCHAR(11), `Column2` VARCHAR(11), `Column3` VARCHAR(11))
;

Eerst hebben we MySQL nodig om getallen te genereren. Deze MySQL-code genereert 1 tot 100. De uiteindelijke query ondersteunt dus maximaal 100 gescheiden waarden.

Zoekopdracht

SELECT 
 @row := @row + 1 AS ROW
FROM (
  SELECT 0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
) row1
CROSS JOIN (
  SELECT 0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
) row2
CROSS JOIN (
  SELECT @row := 0 
) init_user_params 

Resultaat

  row  
--------
       1
       2
       3
       4
       5
       6
       7
       8
       9
      10
     ...
     ...
      90
      91
      92
      93
      94
      95
      96
      97
      98
      99
     100

Nu kunnen we kijken naar een methode om te scheiden op de; scheidingsteken. We kunnen daarvoor geneste SUBSTRING_INDEX-functies gebruiken

Zoekopdracht

SELECT SUBSTRING_INDEX(SUBSTRING_INDEX('Data1;Data2', ';', 1), ';', -1) AS DATA

Resultaat

data    
--------
Data1   

U kunt zien dat alleen het eerste woord wordt geretourneerd als we het tweede woord willen dat we kunnen gebruiken

Zoekopdracht

SELECT SUBSTRING_INDEX(SUBSTRING_INDEX('Data1;Data2', ';', 2), ';', -1) AS DATA

Resultaat

data    
--------
Data2  

Nu combineren we de nummergenerator en de SUBSTRING_INDEX om de gegevens te genereren

Zoekopdracht

SELECT 
  DISTINCT
   SUBSTRING_INDEX(SUBSTRING_INDEX(Column1, ';', rows.row), ';', -1) Column1
 , SUBSTRING_INDEX(SUBSTRING_INDEX(Column2, ';', rows.row), ';', -1) Column2
 , SUBSTRING_INDEX(SUBSTRING_INDEX(Column3, ';', rows.row), ';', -1) Column3
FROM (
  SELECT 
   @row := @row + 1 AS ROW
  FROM (
    SELECT 0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
  ) row1
  CROSS JOIN (
    SELECT 0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
  ) row2  
  CROSS JOIN (
    SELECT @row := 0 
  ) init_user_params
)
 ROWS
CROSS JOIN 
 HugeTable 

Resultaat

Column1  Column2  Column3  
-------  -------  ---------
Data1    Data3    Data5    
Data2    Data4    Data6   

Nieuwe tabel opvragen

INSERT INTO 
  NewTable
SELECT 
  DISTINCT
   SUBSTRING_INDEX(SUBSTRING_INDEX(Column1, ';', rows.row), ';', -1) Column1
 , SUBSTRING_INDEX(SUBSTRING_INDEX(Column2, ';', rows.row), ';', -1) Column2
 , SUBSTRING_INDEX(SUBSTRING_INDEX(Column3, ';', rows.row), ';', -1) Column3
FROM (
  SELECT 
   @row := @row + 1 AS ROW
  FROM (
    SELECT 0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
  ) row1
  CROSS JOIN (
    SELECT 0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
  ) row2  
  CROSS JOIN (
    SELECT @row := 0 
  ) init_user_params
)
 ROWS
CROSS JOIN 
 HugeTable 

Zoekopdracht

SELECT * FROM NewTable

Resultaat

Column1  Column2  Column3  
-------  -------  ---------
Data1    Data3    Data5    
Data2    Data4    Data6