Selecteer aantal / duplicaten

SELECT City, Count(City) As theCount
FROM (Select City, State From tblCityStateZips Group By City, State) As C
GROUP By City
HAVING COUNT Count(City) > 1

Dit zou alle steden teruggeven, met telling, die in meer dan één staat voorkomen.

Greenville 39
Greenwood 2
GreenBriar 3
enz.