Ik heb geen idee waarom de SQL Fiddle anders is dan het daadwerkelijke resultaat, maar het is me gelukt om het voor mij te laten werken in PHP. Gebruik de volgende zoekopdracht:
SELECT
c.procno,
CONCAT(CASE WHEN cnt > 1 THEN CONCAT(RN,'-') ELSE '' END, t.Proc) Proc
FROM
(
SELECT
@curRow:=CASE WHEN @prevRow = a.Proc THEN @curRow+1 ELSE 1 END AS rn,
a.Proc,
a.Procno,
@prevRow:=Proc grp
FROM (
SELECT
`incurredcharges`.`procedure_no` procno,
`c`.`procedure` proc
FROM
incurredcharges
INNER JOIN (
SELECT `procedure`, `procedure_no` FROM `charges`
UNION ALL
SELECT `confinement`, `procedure_no` FROM `confinement`
UNION ALL
SELECT `service`, `procedure_no` FROM `ultrasound`
) c ON `incurredcharges`.`procedure_no` = c.`procedure_no`
WHERE `incurredcharges`.`patient_no` = '34'
ORDER BY `c`.`procedure`
) a
JOIN (SELECT @curRow:=0, @prevRow:= '') r
) t JOIN
(
SELECT
`incurredcharges`.`procedure_no` procno,
`c`.`procedure` proc, Count(*) cnt
FROM
incurredcharges
INNER JOIN (
SELECT `procedure`, `procedure_no` FROM `charges`
UNION ALL
SELECT `confinement`, `procedure_no` FROM `confinement`
UNION ALL
SELECT `service`, `procedure_no` FROM `ultrasound`
) c ON `incurredcharges`.`procedure_no` = c.`procedure_no`
WHERE `incurredcharges`.`patient_no` = '34'
GROUP BY `incurredcharges`.`procedure_no`,
`c`.`procedure`
) c ON t.proc = c.proc
Het enige dat ik heb gewijzigd, was regel 27 van JOIN (SELECT @curRow:=0) r
om JOIN (SELECT @curRow:=0, @prevRow:= '') r