Rijen naar door komma's gescheiden waarden met XML-tag

VOORBEELDTABELLEN

SELECT * INTO Categories
FROM
(
   SELECT 1148 CategoryId, 581771 PostId
   UNION ALL
   SELECT 1183 CategoryId, 581771 PostId
   UNION ALL
   SELECT 1184 CategoryId, 581771 PostId   
)TAB


SELECT * INTO TagContent
FROM
(
SELECT 1 [Id], '<blockquote><p><a href="abc.com"></p></blockquote>' TagContent ,    '2014-11-08' StartDate, '2014-11-14' EndDate,  1148 CategoryID, NULL TagTitle     

UNION ALL   
SELECT  2, '<blockquote><p><a href="abc.com"></p></blockquote>',     '2014-11-25', '2014-12-05',  1183,     '<h1>Aging Title</h1>' 


UNION ALL
SELECT  3, '<blockquote><p><a href="abc.com"></p></blockquote>',     '2014-11-25', '2014-11-27',  1184,     '<h1>Allergies Title</h1>' 
)TAB

Nu converteren we TagTitle naar Amber en gescheiden waarden voor dezelfde TagContent . Aangezien XML-indeling wordt gebruikt, moeten we &gt, &lt and . vervangen &to <, > and & .

QUERY

SELECT DISTINCT TagContent,STUFF(REPLACE(REPLACE(REPLACE(REPLACE(SUBSTRING(
        (SELECT '&' + TagTitle
        FROM TagContent T2 
        WHERE ST.TagContent=T2.TagContent 
        FOR XML PATH('')),2,200000),'&lt;','<'),'&gt;','>'),'&amp;','&'),'amp;',''),1,'') TagTitle
        FROM Categories CPC
        JOIN TagContent ST ON CPC.CategoryId=ST.CategoryId

• SQL FIDDLE