RANK , in plaats van ROW_NUMBER, omdat u wilt dat banden (die met dezelfde B-waarde) dezelfde rangwaarde hebben:
WITH summary AS (
SELECT t.*,
RANK() OVER (PARTITION BY t.id
ORDER BY t.value_type DESC) AS rank
FROM TABLE t
WHERE t.value_type IN ('A', 'B'))
SELECT s.id,
s.value,
s.value_type,
s.data
FROM summary s
WHERE s.rank = 1
Niet CTE-versie:
SELECT s.id,
s.value,
s.value_type,
s.data
FROM (SELECT t.*,
RANK() OVER (PARTITION BY t.id
ORDER BY t.value_type DESC) AS rank
FROM TABLE t
WHERE t.value_type IN ('A', 'B')) s
WHERE s.rank = 1
WITH test AS (
SELECT 1 AS id, 'B' AS value_type
UNION ALL
SELECT 1, 'B'
UNION ALL
SELECT 1, 'A'
UNION ALL
SELECT 2, 'A'
UNION ALL
SELECT 2, 'A'),
summary AS (
SELECT t.*,
RANK() OVER (PARTITION BY t.id
ORDER BY t.value_type DESC) AS rank
FROM test t)
SELECT *
FROM summary
WHERE rank = 1
Ik krijg:
id value_type rank
----------------------
1 B 1
1 B 1
2 A 1
2 A 1