Voorbeeldgegevens:
create table my_table(name text, numbers text[], letters text[]);
insert into my_table values
('first', '{1, 2}', '{a}' ),
('first', '{2, 3}', '{a, b}'),
('second', '{4}', '{c, d}'),
('second', '{5, 6}', '{c}' );
U moet arrays-elementen aggregeren, geen arrays. Gebruik unnest()
:
select
name,
array_agg(distinct number) as numbers,
array_agg(distinct letter) as letters
from
my_table,
unnest(numbers) as number,
unnest(letters) as letter
group by name;
name | numbers | letters
--------+---------+---------
first | {1,2,3} | {a,b}
second | {4,5,6} | {c,d}
(2 rows)
U kunt ook een aangepast aggregaat maken. Je hebt een functie nodig om arrays samen te voegen (aaneenschakeling met het verwijderen van duplicaten):
create or replace function public.array_merge(arr1 anyarray, arr2 anyarray)
returns anyarray language sql immutable
as $$
select array_agg(distinct elem order by elem)
from (
select unnest(arr1) elem
union
select unnest(arr2)
) s
$$;
create aggregate array_merge_agg(anyarray) (
sfunc = array_merge,
stype = anyarray
);
select
name,
array_merge_agg(numbers) as numbers,
array_merge_agg(letters) as letters
from my_table
group by name;