Vind ontbrekende datum en voeg ze toe aan resultaat - MySql

het is misschien geen perfecte oplossing, maar dit zou je het resultaat kunnen geven:de tweede vraag na UNION ALL in de binnenste SELECT zou alle datums moeten retourneren tussen de MIN(created) en de MAX(created) van uw tafel met de tellerwaarde 0.

    SELECT SUM(a.ctr)
      ,a.datecreated
  FROM 
  (

    SELECT COUNT(*) as ctr, date_format(created, '%d/%m/%y ') as datecreated 
    FROM mimesi_indexer.meta_served_clips
    GROUP BY DATE(created)
UNION ALL 
    select 0 as ctr, date_format(selected_date, '%d/%m/%y ') as datecreated 
       from 
     (select adddate('1970-01-01',t4.i*10000 + t3.i*1000 + t2.i*100 + t1.i*10 + t0.i) selected_date from
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) v
    where selected_date 
    between (SELECT MIN(created) FROM mimesi_indexer.meta_served_clips)
        and (SELECT MAX(created) FROM mimesi_indexer.meta_served_clips)
   ) a
   group by a.datecreated
   order by month(a.datecreated), date(a.datecreated)