Meerdere rijen tot één door komma's gescheiden waarde in Sql Server

Testgegevens

DECLARE @Table1 TABLE(ID INT, Value INT)
INSERT INTO @Table1 VALUES (1,100),(1,200),(1,300),(1,400)

Zoekopdracht

SELECT  ID
       ,STUFF((SELECT ', ' + CAST(Value AS VARCHAR(10)) [text()]
         FROM @Table1 
         WHERE ID = t.ID
         FOR XML PATH(''), TYPE)
        .value('.','NVARCHAR(MAX)'),1,2,' ') List_Output
FROM @Table1 t
GROUP BY ID

Resultatenset

╔════╦═════════════════════╗
║ ID ║     List_Output     ║
╠════╬═════════════════════╣
║  1 ║  100, 200, 300, 400 ║
╚════╩═════════════════════╝

SQL Server 2017 en latere versies

Als u met SQL Server 2017 of latere versies werkt, kunt u de ingebouwde SQL Server-functie STRING_AGG gebruiken om de door komma's gescheiden lijst te maken:

DECLARE @Table1 TABLE(ID INT, Value INT);
INSERT INTO @Table1 VALUES (1,100),(1,200),(1,300),(1,400);


SELECT ID , STRING_AGG([Value], ', ') AS List_Output
FROM @Table1
GROUP BY ID;

Resultatenset

╔════╦═════════════════════╗
║ ID ║     List_Output     ║
╠════╬═════════════════════╣
║  1 ║  100, 200, 300, 400 ║
╚════╩═════════════════════╝