Meerdere rijen samenvoegen tot één rij

Hier is A manier om het te doen (werkt ook met 2005):

Tafel

DECLARE @table TABLE
    (
      [Type_ID] INT,
      [Client_ID] VARCHAR(50),
      [PBX_Vendor] VARCHAR(50)
    )

Gegevens

INSERT  INTO @table
        SELECT  127,
                '090820006311404926326C',
                'Aastra'
        UNION ALL
        SELECT  127,
                '090820006311404926326C',
                'Ericsson'
        UNION ALL
        SELECT  127,
                '111012237401404926326C',
                'Aastra'
        UNION ALL
        SELECT  127,
                '120209287521404926326C',
                'Aastra'
        UNION ALL
        SELECT  127,
                '120209287521404926326C',
                'Alcatel'

Zoekopdracht

SELECT  [Type_ID],
        [Client_ID],
        (
          SELECT    STUFF((
                            SELECT  ',' + [PBX_Vendor]
                            FROM    @table
                            WHERE   [Client_ID] = tbl.[Client_ID]
                                    AND [Type_ID] = tbl.[Type_ID]
                            GROUP BY [PBX_Vendor]
                            ORDER BY [PBX_Vendor]
                          FOR
                            XML PATH('')
                          ), 1, 1, '')
        ) PBX_Vendor
FROM    @table tbl
GROUP BY [Type_ID],
        [Client_ID]

Resultaat

Type_ID     Client_ID               PBX_Vendor
127         090820006311404926326C  Aastra,Ericsson
127         111012237401404926326C  Aastra
127         120209287521404926326C  Aastra,Alcatel