Ik denk dat de sleutel hiervoor is om te begrijpen in welke blokken de 188,198 en 88's vallen. In de onderstaande cte werk ik op de basis dat een 88 altijd een blok beëindigt en de rowid van de 88 toewijst aan alle rowids minder dan het - waardoor de groep wordt ingeschakeld.
declare @t table(client_id int, m_id int,chid int,inv_id int,input varchar(20),dt datetime,rowid int)
insert into @t values
(133,928,9581,188,'yes_b1','2016-08-16 01:00:00:000',1),
(133,929,9581,198,'yes_b1','2016-08-16 01:10:00:000',2),
(133,930,9581,82,'referred_b1','2016-08-16 01:30:00:000',3),
(133,935,9584,188,'yes_b2','2016-08-16 01:00:00:000',5),
(133,936,9584,198,'yes_b2','2016-08-16 01:00:00:000',6),
(133,937,9584,82,'referred_b2','2016-08-16 01:00:00:000',7)
;with cte as
(
select s.*,
lag(s.hi,1,0) over (order by s.inv_id) as lo
from
(
select inv_id,rowid as hi
from @t
where inv_id = 82
)s
)
select t.client_id,
max(case when t.inv_id = 188 then input end) 'input(188)',
max(case when t.inv_id = 198 then input end) 'input(198)',
max(case when t.inv_id = 82 then input end) 'input(82)',
max(case when t.inv_id = 188 then dt end) 'date(188)',
max(case when t.inv_id = 198 then dt end) 'date(198)',
max(case when t.inv_id = 82 then dt end) 'date(82)'
from @t t
join cte on rowid <= cte.hi and rowid > cte.lo
group by client_id,cte.hi
Resultaat
client_id input(188) input(198) input(82) date(188) date(198) date(82)
----------- -------------------- -------------------- -------------------- ----------------------- ----------------------- -----------------------
133 yes_b1 yes_b1 referred_b1 2016-08-16 01:00:00.000 2016-08-16 01:10:00.000 2016-08-16 01:30:00.000
133 yes_b2 yes_b2 referred_b2 2016-08-16 01:00:00.000 2016-08-16 01:00:00.000 2016-08-16 01:00:00.000