SQL -- Datums invullen die geen resultaten hebben

Afhankelijk van hoe je ze wilt maken, kun je ofwel een kalendertabel maken of genereer de rijen dynamisch met behulp van de Oracle connect by syntaxis.

with the_dates as (
  select max(trunc(Create_Dtime)) as max_date
       , min(trunc(Create_Dtime)) as min_date
    from player 
         )
  , generator as (
  select min_date + level as the_date
    from the_dates
 connect by level <= max_date
         )
select g.the_date, count(trunc(p.Create_Dtime))
  from generator g
  left outer join player p
    on g.the_date = trunc(p.Create_Dtime)
 group by g.the_date
 order by g.the_date desc

Als je de kalendertabeloptie naar beneden gaat, is het een beetje schoner:

with the_dates as (
  select max(trunc(Create_Dtime)) as max_date
       , min(trunc(Create_Dtime)) as min_date
    from player 
         )
select c.the_date, count(trunc(p.Create_Dtime))
  from calender c
  join the_dates td
    on c.the_date between td.min_date and td.max_date
  left outer join join player p
    on c.the_date = trunc(p.Create_Dtime)
 group by c.the_date
 order by c.the_date

Of, nadat ik zojuist je datumbeperkingen heb opgemerkt:

with the_dates as (
  select to_date('07-05-2012','dd-mm-yyyy') + level as the_date
    from dual
 connect by level <= trunc(to_date('07-05-2012','dd-mm-yyyy') - sysdate)
         )
 select td.the_date, count(trunc(p.create_dtime))
   from the_dates td
   left outer join player p
     on td.the_date = trunc(p.create_dtime)
  group by td.the_date
  order by td.the_date

Voor al deze zou ik een index aanraden op trunc(create_dtime) op je player tafel.