Je kunt het proberen met having
:
SELECT Ads.AdId
FROM Ads
JOIN AdsAmenities ON Ads.AdId = AdsAmenities.ads_AdId
WHERE AdsAmenities.amenities_AmenityId IN (2, 18, 1)
GROUP BY Ads.AdId
HAVING COUNT(distinct AdsAmenities.amenities_AmenityId) = 3
In het geval AdsAmenities.amenities_AmenityId
waarden zijn uniek, u kunt de distinct
overslaan onderdeel.