Goede dag,
Controleer of de onderstaande oplossing al uw behoeften oplost. Ik heb het getest met uw gegevens en met wat meer rijen, maar het is altijd het beste om het opnieuw te controleren. Op het eerste gezicht lijkt het alsof het het gevraagde resultaat retourneert. Ik zal later wat uitleg toevoegen
De vraag die ik gebruik, is dit:
DECLARE @Date DATE = '2018-06-12';
with MyCTE as (
SELECT
t.CustName,t.Country,t.RecordedTime,t.CurrNo, D = CONVERT(DATE, RecordedTime)
,RN_D = ROW_NUMBER()
OVER (partition by t.CustName order by t.CurrNo desc)
,RN = ROW_NUMBER()
OVER (partition by t.CustName order by t.CurrNo)
,RN_Old = ROW_NUMBER()
OVER (partition by t.CustName, (CASE WHEN CONVERT(DATE, RecordedTime) < @Date then 0 else 1 END) order by t.CurrNo desc)
,Cnt = COUNT(*)
OVER (partition by t.CustName)
,CntToday = COUNT(CASE WHEN CONVERT(DATE, RecordedTime) = @Date THEN 1 ELSE NULL END)
OVER (partition by t.CustName)
FROM Test t
where
-- returns rows untill current date
CONVERT (DATE, RecordedTime) <= @Date
-- only if relevnat to current date
and EXISTS (
SELECT * FROM test t0
where CONVERT (DATE, RecordedTime) = @Date and t0.CustName = t.CustName
)
)
,MyCTE2 as (
select
CustName, Country, RecordedTime, D, CurrNo, RN_D, RN, Cnt, t2.c, History, CntToday, RN_Old
from MyCTE t1
left JOIN (select * from (values(1, 'NEW'),(1, 'BEFORE')) t2(c, History) ) t2
on t1.CurrNo = t2.c
and CntToday > 1
and D = @Date
where
RN_D = 1
or (RN = 1 and D = @Date)
or (RN_Old = 1 and D < @Date)
)
,MyCTE3 as (
select CustName, Country, RecordedTime
-- unmarke the bellow comment in order to get the accessories columns I used
-- This is recommended to understand the line-of-thinking
--, D, c, RN_D, RN, CurrNo, Cnt, CntToday, RN_Old
, History = CASE
WHEN CurrNo = 1 and Cnt = 1 then 'NEW'
WHEN RN_D = 1 then 'CURRENT'
else ISNULL(History,'BEFORE')
END
from MyCTE2
)
select CustName, Country, RecordedTime--, D, c, RN_D, RN, CurrNo, Cnt, CntToday, RN_Old
,Audit = CASE when History='New' then 'ADD' else 'CHANGE' END
, History
from MyCTE3
Om het testen eenvoudiger te maken, voeg ik de hele query in de tabelfunctie in
DROP FUNCTION IF EXISTS dbo.F
GO
CREATE FUNCTION dbo.F(@Date DATE)
RETURNS TABLE AS RETURN (
--DECLARE @Date DATE = '2018-06-12';
with MyCTE as (
SELECT
t.CustName,t.Country,t.RecordedTime,t.CurrNo, D = CONVERT(DATE, RecordedTime)
,RN_D = ROW_NUMBER()
OVER (partition by t.CustName order by t.CurrNo desc)
,RN = ROW_NUMBER()
OVER (partition by t.CustName order by t.CurrNo)
,RN_Old = ROW_NUMBER()
OVER (partition by t.CustName, (CASE WHEN CONVERT(DATE, RecordedTime) < @Date then 0 else 1 END) order by t.CurrNo desc)
,Cnt = COUNT(*)
OVER (partition by t.CustName)
,CntToday = COUNT(CASE WHEN CONVERT(DATE, RecordedTime) = @Date THEN 1 ELSE NULL END)
OVER (partition by t.CustName)
FROM Test t
where
-- returns rows untill current date
CONVERT (DATE, RecordedTime) <= @Date
-- only if relevnat to current date
and EXISTS (
SELECT * FROM test t0
where CONVERT (DATE, RecordedTime) = @Date and t0.CustName = t.CustName
)
)
,MyCTE2 as (
select
CustName, Country, RecordedTime, D, CurrNo, RN_D, RN, Cnt, t2.c, History, CntToday, RN_Old
from MyCTE t1
left JOIN (select * from (values(1, 'NEW'),(1, 'BEFORE')) t2(c, History) ) t2
on t1.CurrNo = t2.c
and CntToday > 1
and D = @Date
where
RN_D = 1
or (RN = 1 and D = @Date)
or (RN_Old = 1 and D < @Date)
)
,MyCTE3 as (
select CustName, Country, RecordedTime
-- unmarke the bellow comment in order to get the accessories columns I used
-- This is recommended to understand the line-of-thinking
--, D, c, RN_D, RN, CurrNo, Cnt, CntToday, RN_Old
, History = CASE
WHEN CurrNo = 1 and Cnt = 1 then 'NEW'
WHEN RN_D = 1 then 'CURRENT'
else ISNULL(History,'BEFORE')
END
from MyCTE2
)
select CustName, Country, RecordedTime--, D, c, RN_D, RN, CurrNo, Cnt, CntToday, RN_Old
,Audit = CASE when History='New' then 'ADD' else 'CHANGE' END
, History
from MyCTE3
--order by CustName, RecordedTime
)
GO
Met behulp van de functie is het eenvoudiger om meerdere tests uit te voeren, maar waarschijnlijk wilt u in de productie de directe query gebruiken
-- Test
select * from F('2018-06-01') order by CustName , RecordedTime
select * from F('2018-06-02') order by CustName , RecordedTime
select * from F('2018-06-03') order by CustName , RecordedTime
select * from F('2018-06-10') order by CustName , RecordedTime
select * from F('2018-06-11') order by CustName , RecordedTime
select * from F('2018-06-12') order by CustName , RecordedTime
select * from F('2018-06-13') order by CustName , RecordedTime
select * from F('2018-06-14') order by CustName , RecordedTime
/******************** Update op 19-08-2018 14:05 Israëlische tijd ****************/
Ik merk dat wat meer informatie belangrijk is om toe te voegen omwille van het deelnemen aan de thread. Ik hoop dat dit nuttig zal zijn
Laten we eerst het percentage van het gebruik van resources vergelijken volgens de uitvoeringsplannen van drie zoekopdrachten:(1) mijn oplossing, (2) maulik kansara seconden oplossing na update van de eerste oplossing, en (3) maulik kansara eerste oplossing
Laten we nu de afbeelding van de EP van Maulik Kansara Seconden-oplossing bekijken:
Deze zoekopdracht scant de tabel 11 keer!